(2n+3)^2=2n+12

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Solution for (2n+3)^2=2n+12 equation: 



(2n+3)^2=2n+12

We move all terms to the left:

(2n+3)^2-(2n+12)=0

We get rid of parentheses

(2n+3)^2-2n-12=0

We add all the numbers together, and all the variables

-2n+(2n+3)^2-12=0

We move all terms containing n to the left, all other terms to the right

-2n+(2n+3)^2=12

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